A) \[12{{E}_{1}}+12{{E}_{2}}\]
B) \[13{{E}_{2}}-12{{E}_{1}}\]
C) \[12{{E}_{2}}-13{{E}_{1}}\]
D) \[13{{E}_{2}}+12{{E}_{1}}\]
Correct Answer: B
Solution :
Binding energy of \[{{C}^{12}}\] is \[B{{E}_{1}}=12\times {{E}_{1}}\] Binding energy of \[{{C}^{13}}\] is \[B{{E}_{2}}=13\times {{E}_{2}}\] Thus, energy required to remove one neutron from\[{{C}^{13}}\]is, \[\Delta E=B{{E}_{2}}-B{{E}_{1}}=13{{E}_{2}}-12{{E}_{1}}\]You need to login to perform this action.
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