A) the least in process (ii)
B) greater in process (ii) than in process (i)
C) the same in the processes (i) and (iii)
D) less in process (iii) than in process (ii)
Correct Answer: D
Solution :
Heat absorbed by gas in three processes can be written as \[\Delta {{Q}_{PRQ}}=\Delta U+{{W}_{PRQ}}\] \[\Delta {{Q}_{PSQ}}=\Delta U\] \[\Delta {{Q}_{PTQ}}=\Delta U+{{W}_{PTQ}}\] The change in internal energy in all the three cases is same and\[\Delta {{W}_{PRQ}}>0,\,\,\Delta {{W}_{PTQ}}<0\] Hence, \[\Delta {{Q}_{PRQ}}>\Delta {{Q}_{PSQ}}>\Delta {{Q}_{PTQ}}\]You need to login to perform this action.
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