A) 0.46
B) 0.61
C) 0.95
D) 0.73
Correct Answer: B
Solution :
Key Idea: \[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta n}}\] \[PC{{l}_{3}}(g)+C{{l}_{2}}(g)PC{{l}_{5}}(g)\] \[\therefore \] \[\Delta {{n}_{g}}=1-2=-1\] Given \[{{K}_{c}}=26\] \[T=250{{\,}^{o}}C=250\,+273=523\,K\] \[R=0.0821\] \[\therefore \] \[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta n}}\] \[=26{{(0.0821\,\times \,523)}^{-1}}\] \[=26\times \frac{1}{0.0821\times 523}\] \[=0.61\]You need to login to perform this action.
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