A) 0.96 atm
B) 1.03 atm
C) 2.04 atm
D) 3.08 atm
Correct Answer: B
Solution :
Key Idea: \[\frac{{{P}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}}{{{T}_{2}}}\] Given \[{{P}_{1}}=1\,\text{atm,}\,{{P}_{2}}=?\] \[{{T}_{1}}=25{{\,}^{o}}C=25+273=298K\] \[{{T}_{2}}=35{{\,}^{o}}C=35+273=308K\] \[\frac{1}{298}=\frac{{{P}_{2}}}{308}\] or \[{{P}_{2}}=\frac{308}{298}=1.03\,\text{atm}\]You need to login to perform this action.
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