A) 1
B) 2
C) -1
D) 0
Correct Answer: A
Solution :
1 Roots of \[{{x}^{2}}-x+1=0\]are \[(-\omega ,-{{\omega }^{2}})\] \[\Rightarrow \alpha =-\omega ,\beta =-{{\omega }^{2}}\] \[\Rightarrow {{\alpha }^{101}}+{{\beta }^{107}}\] \[\Rightarrow {{(-\omega )}^{101}}+{{(-{{\omega }^{2}})}^{107}}\] \[\Rightarrow -{{\omega }^{2}}-\omega =1\]You need to login to perform this action.
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