A) \[60\sqrt{3}\]
B) \[36\sqrt{5}\]
C) \[45\sqrt{5}\]
D) \[54\sqrt{3}\]
Correct Answer: C
Solution :
\[\frac{{{x}^{2}}}{9}-\frac{{{y}^{2}}}{36}=1\] Equation of \[P{{Q}_{(T=0)}}\to 0-\frac{y}{12}=1\] \[\because \text{P }\!\!\And\!\!\text{ Q are (}\pm \text{3}\sqrt{5},-12)\] \[\therefore \text{ Area =}\frac{1}{2}6\sqrt{5}\times 15=45\sqrt{5}\]You need to login to perform this action.
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