A) 4
B) \[\frac{9}{2}\]
C) 6
D) \[\frac{7}{2}\]
Correct Answer: B
Solution :
\[2yy=6\] \[18x+2byy=0\] \[{{m}_{1}}{{m}_{2}}=-1\] \[\frac{3}{y}\cdot \left( \frac{-9x}{by} \right)=-1\] \[\frac{x}{{{y}^{2}}}=\frac{b}{27}=\frac{1}{6}\] \[\Rightarrow b=\frac{9}{2}\]You need to login to perform this action.
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