\[x+ky+3z=0\] |
\[3x+ky-2z=0\] |
\[2x+4y-3z=0\] |
A) \[-30\]
B) \[30\]
C) \[-10\]
D) \[10\]
Correct Answer: D
Solution :
For non-zero solution, \[\therefore x+11y=-3z\] ?(1) \[3x+11y=2z\] ?(2) \[-2x=-5z\] ?(1)-(2) \[\Rightarrow x=\frac{5}{2}z\] \[\therefore 11y=-3z-\frac{5}{2}z=-\frac{11}{2}z\Rightarrow y=-\frac{z}{2}\] \[\therefore \frac{xz}{{{y}^{2}}}=\frac{\frac{5}{2}z.z}{\frac{{{z}^{2}}}{4}}=10\]You need to login to perform this action.
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