A) \[\frac{2\,k\,{{\theta }_{0}}^{2}}{l}\]
B) \[\frac{k\,{{\theta }_{0}}^{2}}{l}\]
C) \[\frac{3k\,{{\theta }_{0}}^{2}}{l}\]
D) \[\frac{k\,{{\theta }_{0}}^{2}}{2\,l}\]
Correct Answer: B
Solution :
\[\frac{1}{2}k{{\theta }_{0}}^{2}=\,\,\,\frac{1}{2}\,\left( \frac{m{{l}^{2}}}{9}\,\,+\,\,\frac{m}{2}\,\,\frac{4{{l}^{2}}}{9} \right){{\omega }^{2}}\] \[{{\omega }^{2}}\,\,=\,\,\,m\,\frac{3\,k\,{{\theta }^{2}}}{m{{l}^{2}}}\] \[T\,\,=\,\,m{{\omega }^{2}}\,\frac{l}{3}\,\,=\,\,m\frac{3k{{\theta }^{2}}}{m{{l}^{2}}}\,\,.\,\,\frac{l}{3}\,\,=\,\,\frac{k\,{{\theta }^{2}}_{0}}{l}\] Option is correct.You need to login to perform this action.
You will be redirected in
3 sec