A) 2
B) 3
C) 5
D) 4
Correct Answer: D
Solution :
\[\frac{{{P}^{2}}}{2m}\,\,-\,\,\frac{{{P}^{2}}}{2(2m+M)}\,\,=\,\,\frac{5}{6}\,\,\frac{{{P}^{2}}}{2m}\] \[\frac{1}{m}\,\,-\,\,\frac{1}{(2m+M)}\,\,=\,\,\,\frac{5}{6\,m}\] \[\frac{2m+M-m}{m(2m+M)}\,\,=\,\,\,\frac{5}{6\,m}\] \[6\left( m+M \right)=5\left( 2m+M \right)\] \[6m+6M=10m+5M\] \[4m=M\] \[\frac{m}{M}\,\,=\,\,\frac{1}{4}\] \[\Rightarrow \,\,\frac{M}{m}\,\,=\,\,4\] Option is correct.You need to login to perform this action.
You will be redirected in
3 sec