A) 35
B) 25
C) 66
D) 40
Correct Answer: B
Solution :
\[{{x}_{0}}\to \]Boiling water (\[100{}^\circ C\]) \[\frac{{{x}_{0}}}{3}\to Ice({{0}^{o}}C)\] It means change in length on the linear scale, \[\frac{2{{x}_{0}}}{3}\]corresponds to\[100{}^\circ C\]. 1 corresponds to \[\frac{3\times 100}{2{{x}_{0}}}\] \[\left( \frac{{{x}_{0}}}{2}-\frac{{{x}_{0}}}{3} \right)\]corresponds to\[\frac{3\times 100}{2{{x}_{0}}}\times \frac{{{x}_{0}}}{6}={{25}^{o}}C\]You need to login to perform this action.
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