A) \[40\,\Omega \]
B) \[20\,\Omega \]
C) \[60\,\Omega \]
D) \[30\,\Omega \]
Correct Answer: C
Solution :
Case I: \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{40}{60}=\frac{2}{3}\] ?(i) Case II: \[\frac{{{R}_{1}}+10}{{{R}_{2}}}=1\]or,\[{{R}_{1}}+10={{R}_{2}}\] or\[\frac{2}{3}{{R}_{2}}+10={{R}_{2}};{{R}_{2}}=30\Omega \] \[{{R}_{1}}=\frac{2}{3}\times 30=20\Omega \] Case III: Resistance R is connected in parallel with resistance \[({{R}_{1}}+10)\Omega \] \[\frac{(20+10)\times R}{\frac{30+R}{30}}=\frac{2}{3}\] \[3R=60+2R\] \[R=60\Omega .\]You need to login to perform this action.
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