A) electron
B) \[\alpha \]-particle
C) neutron
D) neutrino
Correct Answer: C
Solution :
The fission of \[_{92}{{U}^{235}}\] is represented by \[_{92}{{U}^{235}}{{+}_{0}}{{n}^{1}}{{\to }_{56}}B{{a}^{141}}{{+}_{36}}K{{r}^{92}}{{+}_{3}}{{n}^{1}}+Q\] The name of the particle x is neutron \[{{(}_{0}}{{n}^{1}})\].You need to login to perform this action.
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