A | |
B | |
C | |
D |
A) A
B) C
C) B
D) D
Correct Answer: C
Solution :
\[e=-\frac{d\phi }{dt}=-\frac{d}{dt}\,(\mathbf{B}\cdot \mathbf{A})\] \[=-A\cos \theta \frac{d}{dt}(B)\] \[=-A\,\cos \,\frac{d}{dt}\,\left[ \frac{{{\mu }_{0}}l}{2{{r}_{1}}} \right]\] \[e=-\frac{A\,\cos \theta {{\mu }_{0}}}{2{{r}_{1}}}\frac{dl}{dt}\] \[e\propto -\frac{dl}{dt}\] Means e will vary as the negative of the variation of slope of l(t).You need to login to perform this action.
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