A) R = 1000 r
B) R = 0.001 r
C) R = 2r
D) R = r
Correct Answer: D
Solution :
Current \[i=\frac{E}{r+R}\] Power generated in R \[P={{i}^{2}}R\] \[P=\frac{{{E}^{2}}R}{{{(r+R)}^{2}}}\] for maximum power\[\frac{dP}{dR}=0\] \[{{E}^{2}}\left[ \frac{{{\left( r+R \right)}^{2}}\times 1-R\times 2\left( r+R \right)}{{{\left( r+R \right)}^{4}}} \right]=0\]\[\Rightarrow r=R\]You need to login to perform this action.
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