A) \[\sqrt{\frac{qE}{2md}}\]
B) \[\sqrt{\frac{qE}{md}}\]
C) \[\sqrt{\frac{2qE}{md}}\]
D) \[\sqrt{\frac{qE}{md}}\]
Correct Answer: C
Solution :
moment of inertia \[(I)=m{{\left( \frac{d}{2} \right)}^{2}}\times 2=\frac{m{{d}^{2}}}{2}\] Now by \[\tau =I\alpha \] \[(qE)(dsin\theta )=\frac{m{{d}^{2}}}{2}.\alpha \] \[\alpha =\left( \frac{2qE}{md} \right)\sin \theta \] for small \[\theta \] \[\Rightarrow \]\[\alpha =\left( \frac{2qE}{md} \right)\theta \] \[\Rightarrow \]Angular frequency \[\omega =\sqrt{\frac{2qE}{md}}\]You need to login to perform this action.
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