A) 5V
B) 2V
C) 3V
D) 1V
Correct Answer: D
Solution :
Charges at inner plates are \[1\mu C\]and \[1\mu C\] \[\therefore \]Potential difference across capacitor \[=\frac{q}{c}=\frac{1\mu C}{1\mu F}=\frac{1\times {{10}^{-6}}C}{1\times {{10}^{-6}}Farad}=1V\]You need to login to perform this action.
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