A) 0.7%
B) 0.2%
C) 3.5%
D) 6.8%
Correct Answer: D
Solution :
\[T=\frac{30\sec }{20}\] \[\Delta T=\frac{1}{20}\sec .\] \[L=55cm\] \[\Delta L=1mm=0.1cm\] \[g=\frac{4{{\pi }^{2}}L}{{{T}^{2}}}\] percentage error in g is \[\frac{\Delta g}{g}\times 100%=\left( \frac{\Delta L}{L}+\frac{2\Delta T}{T} \right)100%\] \[=\left( \frac{0.1}{55}+\frac{2\left( \frac{1}{20} \right)}{\frac{30}{20}} \right)100%\simeq 6.8%\]You need to login to perform this action.
You will be redirected in
3 sec