A) \[\left( \frac{2a}{3},\frac{2b}{3} \right)\]
B) \[\left( \frac{5a}{3},\frac{5b}{3} \right)\]
C) \[\left( \frac{3a}{4},\frac{3b}{4} \right)\]
D) \[\left( \frac{5a}{12},\frac{5b}{12} \right)\]
Correct Answer: D
Solution :
\[x=\frac{M\frac{a}{2}-\frac{M}{4}\times \frac{3a}{4}}{M-\frac{M}{4}}\] \[=\frac{\frac{a}{2}-\frac{3a}{16}}{\frac{3}{4}}=\frac{\frac{5a}{16}}{\frac{3}{4}}=\frac{5a}{12}\] \[y=\frac{M\frac{b}{2}-\frac{M}{4}\times \frac{3b}{4}}{M-\frac{M}{4}}=\frac{5b}{12}\]You need to login to perform this action.
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