A) 320
B) 160
C) 105
D) 210
Correct Answer: D
Solution :
\[p=\frac{n}{\sqrt{2}},\]but\[\frac{n}{\sqrt{2}}<4\Rightarrow n=1,2,3,4,5.\] Length of chord \[AB=2\sqrt{16-\frac{{{n}^{2}}}{2}}\] \[=\sqrt{64-2{{n}^{2}}}=\ell (say)\] For \[n=1,{{\ell }^{2}}=62\] \[n=2,{{\ell }^{2}}=56\] \[n=3,{{\ell }^{2}}=46\] \[n=4,{{\ell }^{2}}=32\] \[n=5,{{\ell }^{2}}=14\] \[\therefore \]Required sum=62+56+46+32+14=210You need to login to perform this action.
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