JEE Main & Advanced
JEE Main Paper (Held on 08-4-2019 Morning)
question_answer
All possible numbers are formed using the digits 1, 1, 2, 2, 2, 2, 3, 4, 4 taken all at a time. The number of such numbers in which the odd digits occupy even places is : [JEE Main 8-4-2019 Morning]
A)175
B)162
C)160
D)180
Correct Answer:
D
Solution :
Number of such numbers \[{{=}^{4}}{{C}_{3}}\times \frac{3!}{2!}\times \frac{6!}{2!4!}=180\]