A) \[{{60}^{o}}\]
B) \[{{15}^{o}}\]
C) \[{{1}^{o}}\]
D) \[{{30}^{o}}\]
Correct Answer: A
Solution :
angular magnfication on \[m=\frac{{{f}_{0}}}{5}\frac{150}{5}=30\] so, \[\frac{\tan \beta }{\tan \alpha }=30\] \[\tan \beta =\tan \alpha \times 30=\left( \frac{50}{1000} \right)\times 30\] \[=\frac{15}{10}=\frac{3}{2}\] \[\beta K\approx {{60}^{o}}\]You need to login to perform this action.
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