A)
B)
C)
D)
Correct Answer: A
Solution :
\[{{V}_{d}}\propto \sqrt{E}\] \[I=neA{{V}_{d}}\] and \[E=\frac{V}{l}\]so \[E\propto V\]and \[I\propto {{V}_{d}}\] so \[I\propto \sqrt{V}\]\[{{I}^{2}}\propto V\]You need to login to perform this action.
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