A) 1.3
B) 0.4
C) 27.0
D) 8.0
Correct Answer: D
Solution :
Bonus \[\zeta \le \sqrt{5gr}\] \[\omega \frac{v}{r}\le \sqrt{\frac{5g}{r}}=\sqrt{\frac{50\times 8}{10}}=\sqrt{\frac{400}{10}}\] \[\omega =\sqrt{40}\]rad/s \[=\frac{60\sqrt{10}}{\pi }\]rpmYou need to login to perform this action.
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