A) \[\frac{3hc}{}\]
B) \[\frac{hc}{}\]
C) \[\frac{hc}{3}\]
D) \[\frac{hc}{2}\]
Correct Answer: D
Solution :
\[K{{E}_{1}}=\frac{hc}{}-W\] ...????.. (i) \[3K.{{E}_{1}}=\frac{2hc}{}-W\] \[\Rightarrow \,K.{{E}_{1}}=\frac{2hc}{3}-\frac{W}{3}\] ???..(ii) \[\Rightarrow \,\frac{hc}{}-W=\frac{2hc}{3}-\frac{W}{3}\] (Equating (i) & (ii)) \[\Rightarrow \,\frac{hc}{}\left( \frac{1}{3} \right)=\frac{2W}{3}\] \[\Rightarrow \,W=\frac{hc}{2}\]You need to login to perform this action.
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