A) \[5\mu C\] from b to a
B) \[20\mu C\] from a to b
C) \[5\mu C\] from a to b
D) zero
Correct Answer: A
Solution :
for upper link \[{{C}_{eq}}=\frac{6}{5}\mu F\] \[\therefore \]\[{{\text{Q}}_{\text{upper}}}={{\text{Q}}_{\text{lower}}}=12\mu C\]on closing switch charge on \[2\mu F\]is \[10\mu C\And \]that on \[3\mu F\]is \[15\mu C\] \[\therefore \]\[{{q}_{i}}=-12+12=0\] \[\therefore \]\[{{q}_{j}}=15-10=5\mu C\] \[\therefore \] \[\]You need to login to perform this action.
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