A) 3V
B) 4V
C) 5V
D) 6V
Correct Answer: C
Solution :
If current in \[4\Omega \] is zero then \[\underset{BCDE}{\mathop{{{\varepsilon }_{v}}}}\,=0\] \[{{V}_{EB}}+{{V}_{BC}}+{{V}_{CD}}+{{V}_{DE}}=0\] \[-4+3+{{V}_{CD}}+0=0\] \[{{V}_{CD}}=1\]volt again \[{{V}_{A}}-9+3+1-{{V}_{D}}=0\] \[{{V}_{A}}-{{V}_{D}}=5V\]You need to login to perform this action.
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