A) \[({{V}_{i}}-{{V}_{L}})/n\,{{I}_{L}}\]
B) \[({{V}_{i}}+{{V}_{L}})/n\,{{I}_{L}}\]
C) \[({{V}_{i}}-{{V}_{L}})/(n+1)\,{{I}_{L}}\]
D) \[({{V}_{i}}+{{V}_{L}})/(n+1)\,{{I}_{L}}\]
Correct Answer: C
Solution :
Voltage drop across zener diode is \[{{V}_{L}}\]so voltage drop across S \[{{K}_{s}}\] \[{{K}_{Rs}}={{V}_{i}}-{{V}_{L}}=\left( n+1 \right){{I}_{L}}{{R}_{s}}\] \[{{K}_{s}}=\frac{{{V}_{i}}-{{V}_{L}}}{\left( n+1 \right){{I}_{L}}}\]You need to login to perform this action.
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