A) 1/2
B) -3/2
C) 3/2
D) -1/2
Correct Answer: A
Solution :
Maxima of f(x) occured at \[x=2\]i.e. \[\alpha =2\] Minima of g(x) occured at \[x=1\] i.e. \[\beta =-1\] \[\therefore \]\[\underset{x\to 2}{\mathop{\lim }}\,\frac{\left( x-1 \right)\left( x-2 \right)\left( x-3 \right)}{\left( x-2 \right)\left( x-4 \right)}=\frac{1}{2}\]You need to login to perform this action.
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