A) \[15\left( 3-\sqrt{3} \right)\]
B) \[15\left( 3+\sqrt{3} \right)\]
C) \[15\left( 1+\sqrt{3} \right)\]
D) \[15\left( 5-\sqrt{3} \right)\]
Correct Answer: B
Solution :
\[\tan {{45}^{o}}=1=\frac{x+30}{y}\Rightarrow x+30=y\] (i) \[\tan {{30}^{o}}=\frac{1}{\sqrt{3}}=\frac{x}{y}\Rightarrow x=\frac{y}{\sqrt{3}}\] (ii) from (i) and (ii) \[y=15\left( 3+\sqrt{3} \right)\]You need to login to perform this action.
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