A) \[1=\frac{1n\lambda }{\sqrt{3}-1}\]
B) \[1=\frac{(2n-1)\lambda }{2\left( \sqrt{3}-1 \right)}\]
C) \[1=\frac{(2n-1)\lambda \sqrt{3}}{4\left( 2-\sqrt{3} \right)}\]
D) \[1=\frac{(2n-1)\lambda }{\sqrt{3}-1}\]
Correct Answer:
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