A) \[\text{3300}\overset{\text{o}}{\mathop{\text{A}}}\,\]
B) \[\text{4400}\overset{\text{o}}{\mathop{\text{A}}}\,\]
C) \[\text{5500}\overset{\text{o}}{\mathop{\text{A}}}\,\]
D) \[\text{6600}\overset{\text{o}}{\mathop{\text{A}}}\,\]
Correct Answer: B
Solution :
In a single slit experiment, For diffraction maxima, \[a\sin \theta =(2n+1)\frac{\lambda }{2}\]and for diffraction minima, \[a\sin \theta =n\lambda \] According to question, \[(2\times 1+1)\frac{\lambda }{2}=1\times 6600\] \[(\because {{\lambda }_{R}}=6600{A})\] \[\lambda =\frac{6600\times 2}{3}\] \[\lambda =4400{A}\]You need to login to perform this action.
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