A) \[\beta \frac{{{R}_{L}}}{{{R}_{BE}}},\frac{\Delta {{I}_{E}}}{\Delta {{I}_{B}}},{{\beta }^{2}}\frac{{{R}_{L}}}{{{R}_{BE}}}\]
B) \[{{\beta }^{2}}\frac{{{R}_{L}}}{{{R}_{BE}}},\frac{\Delta {{I}_{C}}}{\Delta {{I}_{B}}},\beta \frac{{{R}_{L}}}{{{R}_{BE}}}\]
C) \[{{\beta }^{2}}\frac{{{R}_{L}}}{{{R}_{BE}}},\frac{\Delta {{I}_{C}}}{\Delta {{I}_{B}}},{{\beta }^{2}}\frac{{{R}_{L}}}{{{R}_{BE}}}\]
D) \[\beta \frac{{{R}_{L}}}{{{R}_{BE}}},\frac{\Delta {{I}_{C}}}{\Delta {{I}_{B}}},{{\beta }^{2}}\frac{{{R}_{L}}}{{{R}_{BE}}}\]
Correct Answer: D
Solution :
Voltage gain = \[\frac{{{V}_{CE}}}{{{V}_{BE}}}=\beta \frac{{{R}_{L}}}{{{R}_{BE}}}\] Current gain \[=\beta =\frac{{{I}_{C}}}{{{I}_{B}}}\] \[\text{Power gain=voltage gain}\times \text{current gain=}{{\beta }^{2}}\frac{{{R}_{L}}}{{{R}_{BE}}}\]You need to login to perform this action.
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