A) \[\text{19}\text{.15 }\Omega \] and \[\text{39}\text{.5 cm}\]
B) \[\text{8}\text{.16 }\Omega \text{ and 60}\text{.5 cm}\]
C) \[\text{19}\text{.15}\,\,\text{ }\!\!\Omega\!\!\text{ }\,\,\text{and}\,\,\text{60}\text{.5}\,\,\text{cm}\]
D) \[\text{8}\text{.16}\,\,\Omega \text{ and 39}\text{.5 cm}\]
Correct Answer: B
Solution :
\[\frac{X}{Y}=\] \[\frac{39.5}{60.5}\] \[X=\frac{39.5}{60.5}\times 12.5\] \[=8.16\,\,\,\Omega \] \[\frac{12.5}{8.16}=\frac{{{l}_{2}}}{100-{{l}_{2}}}\] \[1.53(100+{{l}_{2}})={{l}_{2}}\] \[153-1.53\,\,{{l}_{2}}={{l}_{2}}\] \[\frac{153}{2.53}={{l}_{2}}\] \[=60.5cm\]You need to login to perform this action.
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