A) A increasing the pressure
B) addition of an inert gas at constant pressure
C) lowering the temperature
D) addition of an inert gas at constant volume
Correct Answer: B
Solution :
reaction at equilibirium (1) according to Le chatelier's principle- Increasing the pressure on a gas reaction shifts the position of equilibirium towards the side with fewer molecules. So, It will move in backward direction which leads to formation of\[{{N}_{2}}{{O}_{4}}\]from\[N{{O}_{2}}.\]So option (1) is correct. (2)addition of an inert gas at constant pressure will increases volume and equilibirium shifts towards more number of molecules. (3) Decomposition of will be endothermic, so reaction will move in forward reaction when temperature is increased. So, It is incorrect. It will not effect reaction (volume is constant)You need to login to perform this action.
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