A)
B)
C)
D)
Correct Answer: A
Solution :
Displacement \[y(t)=A\sin (wt+\phi )\][Given] For \[\phi =\frac{2\pi }{3}\]at\[t=0;y=A\sin \phi =A\sin \frac{2\pi }{3}\] \[=A\sin {{120}^{o}}=0.87A[\because \sin {{120}^{o}}\simeq 0.866]\] Graph (a) depicts y = 0.87.4 at t = 0You need to login to perform this action.
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