A) \[90{}^\circ C\]
B) \[50{}^\circ C\]
C) \[10{}^\circ C\]
D) \[67{}^\circ C\]
Correct Answer: A
Solution :
Let conductivity of steel \[{{K}_{steel}}=k\]then from question Conductivity of copper\[{{K}_{copper}}=9k\] \[{{\theta }_{copper}}={{100}^{o}}C\] \[{{\theta }_{steel}}={{0}^{o}}C\] \[{{I}_{steel}}={{I}_{copper}}=\frac{L}{2}\] From formula temperature of junction; \[\theta =\frac{{{K}_{copper}}{{\theta }_{copper}}{{l}_{steel}}+{{K}_{steel}}{{\theta }_{steel}}{{l}_{copper}}}{{{K}_{copper}}{{l}_{steel}}+{{K}_{steel}}{{l}_{copper}}}\] \[=\frac{9k\times 100\times \frac{L}{2}+k\times 0\times \frac{L}{2}}{9k\times \frac{L}{2}+k\times \frac{L}{2}}\] \[=\frac{\frac{900}{2}kL}{\frac{10kL}{2}}={{90}^{o}}C\]You need to login to perform this action.
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