A) 0.3 M
B) 0.2 M
C) 0.6 M
D) 1.8 M
Correct Answer: B
Solution :
\[\underset{\begin{smallmatrix} 100ml \\ m=? \end{smallmatrix}}{\mathop{3NaOH+Fec{{l}_{3}}}}\,\to \underset{2.14gm}{\mathop{Fe{{(CH)}_{3}}+NaCl}}\,\] Moles of \[Fe(C{{H}_{3}})=\frac{2.14}{107}=2\times {{10}^{-2}}mol\] moles \[FeC{{l}_{3}}=2\times {{10}^{-2}}mol\] \[M=\frac{2\times {{10}^{-2}}}{100}\times 1000=0.2M\]You need to login to perform this action.
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