A) 25 g
B) 65 g
C) 15 g
D) 45 g
Correct Answer: D
Solution :
\[N{{a}_{2}}S{{O}_{4}}\to 2N{{a}^{+}}+SO_{4}^{2-}\] \[x=1+(3-1)0.815=2.63\] \[3.82=1.86\times 2.63\times \frac{5\times 1000}{142\times X}\] \[\therefore \]\[X=\frac{1.86\times 2.63\times 5000}{142\times 3.82}\]=45gmYou need to login to perform this action.
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