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JEE Main & Advanced JEE Main Paper (Held On 9 April 2014)

  • question_answer
    When the rms voltages \[{{V}_{L}},{{V}_{C}}\]and \[{{V}_{R}}\] are measured respectively across the inductor L, the capacitor C and the resistor R in a series LCR circuit connected to an AC source, it is found that the ratio \[{{V}_{L}}:{{V}_{C}}:{{V}_{R}}=1:2:3.\]If the rms voltage of the AC sources is 100 V, the \[{{V}_{R}}\] is close to:   [JEE Main Online Paper ( Held On 09 Apirl  2014  )

    A) 50 V                      

    B) 70 V

    C) 90 V

    D) 100 V

    Correct Answer: C

    Solution :

                    Given, \[{{V}_{L}}:{{V}_{C}}:{{V}_{R}}=1:2:3\] \[V=100V\] \[{{V}_{R}}=?\]As we know,\[V=\sqrt{V_{R}^{2}+{{\left( {{V}_{L}}-{{V}_{C}} \right)}^{2}}}\] Solving we get, \[{{V}_{R}}\simeq 90V\]                                


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