JEE Main & Advanced JEE Main Paper (Held On 9 April 2014)

Match List I (Wavelength range of electromagnetic spectrum)with List II (Method of production of these waves) and select the correct option from the options given below the lists.

List I List II

(1) 700 nm to 1 mn (i) Vibration of atoms and molecules.

(2) 1 nm to 400 nm (ii) Inner shell electrons in atoms moving from one energy level to a lower level.

(3)\[<{{10}^{-3}}nm\] (iii) Radioactive decay of the nucleus.

(4) 1 mm to 0.1 m (iv) Magnetron valve.

[JEE Main Online Paper ( Held On 09 Apirl 2014 )

A) (1)-(iv), (2)-(iii), (3)-(ii), (4)-(i)

B) (1)-(iii), (2)-(iv), (3)-(i), (4)-(ii)

C) (1)-(ii), (2)-(iii), (3)-(iv), (4)-(i)

D) (1)-(i), (2)-(ii), (3)-(iii), (4)-(iv)

Correct Answer: D

Solution :

Vibration of atoms and molecules 700 nm to 1 mm Radioactive decay of the nucleus \[<{{10}^{-3}}nm\]Magnetron valve 1 mm to 0.1 m

List I	List II
(1) 700 nm to 1 mn	(i) Vibration of atoms and molecules.
(2) 1 nm to 400 nm	(ii) Inner shell electrons in atoms moving from one energy level to a lower level.
(3)\[<{{10}^{-3}}nm\]	(iii) Radioactive decay of the nucleus.
(4) 1 mm to 0.1 m	(iv) Magnetron valve.