A) 0.25 mol
B) 0.125 mol
C) 0.333 mol
D) 0.50 mol
Correct Answer: B
Solution :
\[{{H}_{3}}As{{O}_{4}}\xrightarrow[{}]{{{H}_{2}}S/HCl}A{{s}_{2}}{{S}_{5}}\] Assuming 100% conversion of As, apply POAC rule for 'As' atom \[1\times {{n}_{{{H}_{3}}AsO{{ & }_{4}}}}=2\times {{n}_{A{{s}_{2}}{{O}_{5}}}}\] \[\frac{35.5}{142}=2\times {{n}_{A{{s}_{2}}{{O}_{5}}}}\]\[\therefore \]\[{{N}_{A{{s}_{2}}O{{ & }_{5}}}}=0.125mol\]You need to login to perform this action.
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