A) 0.02
B) 0.015
C) 0.0075
D) 0.005
Correct Answer: B
Solution :
According to Henery law\[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{S}_{1}}}{{{S}_{2}}}\] \[\therefore \]\[{{S}_{1}}\And {{S}_{2}}\]are solubility of gas (g/L) \[\frac{500}{750}=\frac{0.01}{{{S}_{2}}}\] \[\therefore \]\[{{S}_{2}}=\frac{750\times 0.01}{500}=0.015g/L\]You need to login to perform this action.
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