A) 1.75 mm
B) 2.0 mm
C) 1.50mm
D)
1.25 mm Correct Answer:
D Solution :
\[\Rightarrow \,1\times {{10}^{11}}\,\times \,\left( \frac{1\times {{10}^{-3}}}{1} \right)\,=2\times {{10}^{11}}\,\times \left( \frac{\Delta {{L}_{s}}}{0.5} \right)\] \[\therefore \]\[\Delta {{L}_{s}}=\frac{0.5\times {{10}^{-3}}}{2}=0.25mm\] Therefore, total extension of the composite wire \[=\Delta {{L}_{c}}+\Delta {{L}_{s}}\] \[=1\,mm+0.25m=1.25m\]
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