Two blocks of masses m and M are connected by means of a metal wire of cross-sectional area A Passing over a frictionless fixed pulley as shown in the figure. The system is then released. If \[\operatorname{M}=2\] m, then the stress produced in the wire is: [JEE ONLINE 25-04-2013] |
A) \[\frac{2\operatorname{mg}}{3A}\]
B)
\[\frac{4\operatorname{mg}}{3A}\] C)
\[\frac{\operatorname{mg}}{A}\]
D)
\[\frac{3\operatorname{mg}}{4A}\]
Correct Answer:
B Solution :
Stress\[=\frac{Force/Tension}{Area}=\frac{2mM}{A(m+M)}g\] \[=\frac{2(m\times 2m)g}{A(m+2m)}=(M=2m\,\text{given})\] \[=\frac{4{{m}^{2}}}{3mA}g=\frac{4mg}{3A}\]
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