An LCR circuit is equivalent to a damped pendulum. In an LCR circuit the capacitor is charged to \[{{Q}_{0}}\]and then connected to the L and R as shown below: |
If a student plots graphs of the square of maximum charge \[\left( Q_{Max}^{2} \right)\]on the capacitor with time (t) for two different values \[{{L}_{1}}\] and \[{{L}_{2}}\] \[\left( {{L}_{1}}>{{L}_{2}} \right)\]of L then which of the following represents this graph correctly? (plots are schematic and not drawn of scale) [JEE MAIN 2015] |
A)
B)
C)
D)
Correct Answer: C
Solution :
[c] \[-\frac{q}{C}-iR=\frac{Ldi}{dT}=0\]You need to login to perform this action.
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