A) 3H
B) 1.67 H
C) 6 H
D) 0.67 H
Correct Answer: B
Solution :
[b] |
\[{{I}_{1}}=5A\] \[{{I}_{2}}=2A\] |
\[\Delta I=2-5=-3A\] |
\[\Delta t=0.1\sec \] |
\[Emf=50v\] |
\[emf=\varepsilon =-L\frac{di}{dt}\] |
\[50=-L\left( \frac{-3}{0.1} \right)\] |
\[50=30L\] |
\[L=\frac{5}{3}=1.67H\] |
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