The magnetic field of a plane electromagnetic wave is given by : |
\[\vec{B}={{B}_{0}}\hat{i}[cos(kz-\omega t)]+{{B}_{1}}\hat{j}\cos (kz+\omega t)\] where \[{{B}_{0}}=3\times {{10}^{-5}}T\] and \[{{B}_{1}}=2\times {{10}^{-6}}T.\] The rms value of the force experienced by a stationary charge \[Q={{10}^{-4}}C\]at \[z=0\]is closest to : [JEE Main 9-4-2019 Morning] |
A) \[0.9\text{ }N\]
B) \[0.1\text{ }N\]
C) \[3\times {{10}^{2}}N\]
D) \[0.6N\]
Correct Answer: D
Solution :
[d] Maximum Electric field E = [b] [c] |
Maximum force |
(approx) |
Option [d] |
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