The electric field of a plane electromagnetic wave is given by \[\vec{E}={{E}_{0}}\hat{i}\cos (kz)cos(\omega t)\] |
The corresponding magnetic field \[\vec{B}\]is then given by: [JEE Main 10-4-2019 Morning] |
A) \[\vec{B}=\frac{{{E}_{0}}}{C}\hat{j}\sin (kz)cos(\omega t)\]
B) \[\vec{B}=\frac{{{E}_{0}}}{C}\hat{j}\sin (kz)sin(\omega t)\]
C) \[\vec{B}=\frac{{{E}_{0}}}{C}\hat{k}\sin (kz)cos(\omega t)\]
D) \[\vec{B}=\frac{{{E}_{0}}}{C}\hat{j}\sin (kz)sin(\omega t)\]
Correct Answer: B
Solution :
[b] |
Given that wave is propagating along positive z-axis and along positive x-axis. Hence along y-axis. |
From Maxwell equation |
i.e.and |
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