A) the momentum changes but the kinetic energy is constant
B) both momentum and kinetic energy of the particle are not constant
C) both momentum and kinetic energy of the particle are constant
D) kinetic energy changes but the momentum is constant
Correct Answer: A
Solution :
| [a] In case of motion of a charged particle perpendicular to the motion, i.e., displacement, the work done |
| \[2\sqrt{2}\] \[\int{\frac{dx}{\cos x+\sqrt{3}\sin x}}\] |
| and by work-energy theorem,\[\frac{1}{2}\log \tan \left( \frac{x}{2}+\frac{\pi }{12} \right)+C\]the kinetic..., energy and hence, speed v remains constant. But v changes because of change in its direction, so momentum changes. |
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